
Calculate structural similarity among solutions
Source:R/analysis_selection.R
selection_similarity.RdCalculate pairwise structural similarity among the stored solutions in a
solutionset-class object.
Arguments
- x
A
solutionset-classobject returned bysolve.- metric
Character. Similarity metric to use. One of
"jaccard"or"hamming".- format
Character. Output format. If
"long", return one row per pair of solutions. If"matrix", return a symmetric similarity matrix with solution ids as row and column names.
Value
The two solution-id columns are returned as integers.
If format = "long", a data.frame with columns:
solution_id_1;solution_id_2;similarity;distance.
If format = "matrix", a symmetric numeric matrix of similarities is
returned. Its diagonal is equal to one.
The selected metric is stored in the "metric" attribute.
Details
Solutions are compared using their complete planning-unit/action assignment vectors. Consequently, two solutions that select the same planning unit but assign different actions are treated as structurally different.
For simple conservation-planning problems without explicit actions,
selected planning units are represented using the canonical action name
"conservation".
Two similarity metrics are supported:
"jaccard"compares the sets of selected planning-unit/action assignments:$$ J(A,B) = \frac{|A \cap B|} {|A \cup B|}. $$
Jaccard similarity focuses on selected assignments and ignores joint absences. It is generally the preferred metric for sparse conservation and management portfolios.
"hamming"calculates the proportion of decision-vector positions that are equal:$$ H(A,B) = \frac{1}{m} \sum_{k=1}^{m} I(A_k = B_k), $$
where \(m\) is the number of feasible planning-unit/action assignments. Unlike Jaccard similarity, Hamming similarity includes shared non-selections.
For both metrics, similarity ranges from zero to one:
1indicates identical assignment structures;0indicates no structural agreement under the selected metric.
The corresponding distance is calculated as:
$$ D(A,B) = 1 - S(A,B). $$
The comparison is performed over all stored solutions in the supplied
object. To compare only a subset, first use
solution_filter or solution_unique.
Examples
# Load a complete simulated planning problem.
example_data <- load_sim_multiaction()
problem <- create_problem(
pu = example_data$planning_units,
features = example_data$features,
dist_features = example_data$dist_features,
cost = "cost"
) |>
add_actions(
example_data$actions,
cost = example_data$action_costs
) |>
add_effects(
example_data$effects,
effect_type = "delta"
) |>
add_constraint_targets_relative(0.05) |>
add_objective_min_cost(alias = "cost", include_pu_cost = FALSE) |>
add_objective_max_benefit(alias = "benefit") |>
set_method_weighted_sum(
aliases = c("cost", "benefit"),
runs = set_runs_grid(n = 3),
normalize_weights = TRUE
)
if (requireNamespace("rcbc", quietly = TRUE)) {
problem <- set_solver_cbc(
problem,
verbose = FALSE
)
solutions <- solve(problem)
# Pairwise Jaccard similarity in long format
jaccard_long <- selection_similarity(
solutions
)
jaccard_long
# Symmetric Jaccard similarity matrix
jaccard_matrix <- selection_similarity(
solutions,
format = "matrix"
)
jaccard_matrix
# Hamming similarity includes shared non-selections
hamming_long <- selection_similarity(
solutions,
metric = "hamming"
)
hamming_long
# Compare only structurally unique solutions
unique_solutions <- solution_unique(
solutions,
by = "decisions"
)
selection_similarity(
unique_solutions,
format = "matrix"
)
}
#> 1 2 3
#> 1 1.00000000 0.00000 0.01538462
#> 2 0.00000000 1.00000 0.03125000
#> 3 0.01538462 0.03125 1.00000000
#> attr(,"metric")
#> [1] "jaccard"